y=[]
n=int(raw_input('Enter the no of elements added to list:'))
index=0
for i in range(n):
element=int(raw_input('Enter the elements:'))
y.insert(index, element)
index=index+1
print y
Solve Problems by Coding Solutions - A Complete solution for python programming
To add elements inside a list using append
l=[]
n=int(raw_input('Enter the no of elements added to list:'))
for i in range(n):
element=int(raw_input('Enter the elements:'))
l.append(element)
print l
n=int(raw_input('Enter the no of elements added to list:'))
for i in range(n):
element=int(raw_input('Enter the elements:'))
l.append(element)
print l
To count the elements in a nested list with all elements are list
a=[[3, 4, 5,8, 8 ], [5, 6, 7], [7, 8, 9]]
def count(a):
j=0
n=0
for b in a:
j=len(b)
n=n+j
return n
t= count(a)
print "No elements in the nested list are:",t
def count(a):
j=0
n=0
for b in a:
j=len(b)
n=n+j
return n
t= count(a)
print "No elements in the nested list are:",t
Count of character repetition in a string
word=str(raw_input('Enter the string:'))
n=raw_input('Enter the character to search in string:')
c=0
for i in word:
if i==n:
c=c+1
print 'Number of times the character repeated is', c
n=raw_input('Enter the character to search in string:')
c=0
for i in word:
if i==n:
c=c+1
print 'Number of times the character repeated is', c
To check a string is palidrome or not
k=raw_input('Enter a string: ')
if k==k[::-1]:
print 'String is palidrome'
else:
print 'String is not palidrome'
if k==k[::-1]:
print 'String is palidrome'
else:
print 'String is not palidrome'
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