# Credits to NPTEL MOOC,Programming, Data Structures & Algorithms
#in
Python by Madhavan Mukund, Chennai Mathematical Institute
def gcd(m,n):
if m < n: # Assume m >= n
(m,n) = (n,m)
while (m%n) != 0:
diff = m-n
# diff > n? Possible!
(m,n) = (max(n,diff),min(n,diff))
return(n)
Solve Problems by Coding Solutions - A Complete solution for python programming
Greatest common divisor program using euclids algorithms
#Credits to NPTEL MOOC, Programming, Data Structures & Algorithms in #Python by Madhavan Mukund, Chennai Mathematical Institute
def gcd(m,n):
if m < n:
(m,n) = (n,m)
if (m%n) == 0:
return(n)
else:
diff = m-n
return(gcd(max(n,diff),min(n,diff)))
print(gcd(12,3))
Greatest common divisor program with looping
#Credits to NPTEL MOOC, Programming, Data Structures & Algorithms in #Python by Madhavan Mukund, Chennai Mathematical Institute
def gcd(m,n):
i = min(m,n)
while i > 0:
if (m%i) == 0 and (n%i) == 0:
return(i)
else:
i = i-1
Greatest common divisor program without list Implementation
#Credits to NPTEL MOOC, Programming, Data Structures & Algorithms in #Python by Madhavan Mukund, Chennai Mathematical Institute
def gcd(m,n):
for i in range(1,min(m,n)+1):
if (m%i) == 0 and (n%i) == 0:
mrcf = i
return(mrcf)
Greatest common divisor program - A shorter Implementation
#Credits to NPTEL MOOC, Programming, Data Structures & Algorithms #in
Python by Madhavan Mukund, Chennai Mathematical Institute
def gcd(m,n):
cf = []
for i in range(1,min(m,n)+1):
if (m%i) == 0 and (n%i) == 0:
cf.append(i)
return(cf[-1])
def gcd(m,n):
cf = []
for i in range(1,min(m,n)+1):
if (m%i) == 0 and (n%i) == 0:
cf.append(i)
return(cf[-1])
Greatest common divisor program
#Credits to NPTEL MOOC, Programming, Data Structures & Algorithms in #Python by Madhavan Mukund, Chennai Mathematical Institute
def gcd(m,n):
fm = []
for i in range(1,m+1):
if (m%i) == 0:
fm.append(i)
fn = []
for j in range(1,n+1):
if (n%j) == 0:
fn.append(j)
cf = []
for f in fm:
if f in fn:
cf.append(f)
return(cf[-1])
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