Check if a given string is binary string or not

def check(string) :

p = set(string)

s = {'0', '1'}

if s == p or p == {'0'} or p == {'1'}:

print("Yes")

else :

print("No")

if __name__ == "__main__" :

string = "101010000111"

check(string)

Using itemgetter sort list of dictionaries by values

from operator import itemgetter

lis = [{ "name" : "Pooja", "age" : 22},

{ "name" : "Arjun", "age" : 20 },

{ "name" : "Nikhil" , "age" : 19 }]

print ("The list printed sorting by age:")

print (sorted(lis, key=itemgetter('age')))

print ("\r")

print ("The list printed sorting by age and name:")

print (sorted(lis, key=itemgetter('age', 'name')))

print ("\r")

print ("The list printed sorting by age in descending order:")

print (sorted(lis, key=itemgetter('age'),reverse = True))