import math
def digSum( n):
sum = 0
while(n > 0 or sum > 9):
if(n == 0):
n = sum
sum = 0
sum += n % 10
n /= 10
return sum
n = 1234
print (digSum(n))
Solve Problems by Coding Solutions - A Complete solution for python programming
import math
def digSum( n):
sum = 0
while(n > 0 or sum > 9):
if(n == 0):
n = sum
sum = 0
sum += n % 10
n /= 10
return sum
n = 1234
print (digSum(n))
def hasConsecutiveZeroes(N, K):
z = toK(N, K)
if (check(z)):
print("Yes")
else:
print("No")
def toK(N, K):
w = 1
s = 0
while (N != 0):
r = N % K
N = N//K
s = r * w + s
w = 10
return s
def check(N):
fl = False
while (N != 0):
r = N % 10
N = N//10
if (fl == True and r == 0):
return False
if (r > 0):
fl = False
continue
fl = True
return True
N, K = 15, 8
hasConsecutiveZeroes(N, K)
import math
def calculateDivisors (A, B):
N = A - B
noOfDivisors = 0
a = math.sqrt(N)
for i in range(1, int(a + 1)):
if ((N % i == 0)):
if (i > B):
noOfDivisors +=1
if ((N / i) != i and (N / i) > B):
noOfDivisors += 1;
return noOfDivisors
def numberOfPossibleWaysUtil (A, B):
if (A == B):
return -1
if (A < B):
return 0
noOfDivisors = 0
noOfDivisors = calculateDivisors;
return noOfDivisors
def numberOfPossibleWays(A, B):
noOfSolutions = numberOfPossibleWaysUtil(A, B)
if (noOfSolutions == -1):
print ("For A = " , A , " and B = " , B
, ", X can take Infinitely many values"
, " greater than " , A)
else:
print ("For A = " , A , " and B = " , B
, ", X can take " , noOfSolutions
, " values")
A = 26
B = 2
numberOfPossibleWays(A, B)
A = 21
B = 5
numberOfPossibleWays(A, B)
import turtle as t
pen = t.Turtle()
pen.color("cyan")
pen.speed(0)
colors = ["green","black","orange","navy","green","black","orange","navy"]
def draw_square(color):
for side in range(4):
pen.forward(100)
pen.right(90)
for side in range(4):
pen.forward(50)
pen.right(90)
pen.penup()
pen.back(40)
pen.pendown()
for color in colors:
pen.color(color)
draw_square(color)
pen.forward(50)
pen.left(45)
pen.hideturtle()
t.done()
def PrintNumber(N, Original, K, flag):
print(N, end = " ")
if (N <= 0):
if(flag==0):
flag = 1
else:
flag = 0
if (N == Original and (not(flag))):
return
if (flag == True):
PrintNumber(N - K, Original, K, flag)
return
if (not(flag)):
PrintNumber(N + K, Original, K, flag);
return
N = 20
K = 6
PrintNumber(N, N, K, True)