R = 3
C = 3
def minCost(cost, m, n):
tc = [[0 for x in range(C)] for x in range(R)]
tc[0][0] = cost[0][0]
for i in range(1, m + 1):
tc[i][0] = tc[i-1][0] + cost[i][0]
for j in range(1, n + 1):
tc[0][j] = tc[0][j-1] + cost[0][j]
for i in range(1, m + 1):
for j in range(1, n + 1):
tc[i][j] = min(tc[i-1][j-1], tc[i-1][j],tc[i][j-1]) + cost[i][j]
return tc[m][n]
cost = [[1, 2, 3],
[4, 8, 2],
[1, 5, 3]]
print(minCost(cost, 2, 2))
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