def Fah():

F=int(input('Enter the temperature on Fahrenheit(F)'))

C=(F - 32) * 5/9

K=(F - 32) * 5/9 + 273.15

print("Fahrenheit Value :",F)

print("Celsius Value :",C)

print("Kelvin Value:",K)

def Cel():

C=int(input('Enter the temperature on Celsius(C)'))

F=(C * 9/5) + 32

K=C + 273.15

print("Fahrenheit Value :",F)

print("Celsius Value :",C)

print("Kelvin Value:",K)

def Kel():

K=int(input('Enter the temperature on Kelvin(K)'))

F=(K - 273.15) * 9/5 + 32

C=K - 273.15

print("Fahrenheit Value :",F)

print("Celsius Value :",C)

print("Kelvin Value:",K)

print("\n")

print('1.Fahrenheit to Celsius & Kelvin\n2.Celsius to Fahrenheit & Kelvin\n3.Kelvin to Fahrenheit & Celsius\n4.Exit')

n=int(input('Enter the choice:'))

if n==1:

Fah()

elif n==2:

Cel()

elif n==3:

Kel()

elif n==4:

exit()

else:

print('Invalid options')

Solve Problems by Coding Solutions - A Complete solution for python programming

### Newton Raphson Method

# Newton Raphson Method

# The Newton-Raphson method (also known as Newton's method) is a way

# to quickly find a good approximation for the root of a real-valued function

xcube=int(input('Enter the values for Xcube: '))

xsquare=int(input('Enter the values for Xsquare: '))

x=int(input('Enter the values for X: '))

constant=int(input('Enter the values for Constant: '))

X0=int(input('Enter the values for inital vaule X0: '))

# It can be any value, but based on the incorrectness the root convergence

# will delay. Here we can use trail and error method for input value.

X1= X0-((((xcube*X0*X0*X0)+(xsquare*X0*X0)+(x*X0)+constant)/((xcube*3*X0*X0)+(xsquare*2*X0)+x)))

print ("Root at first approximations:",X1)

X2= X1-((((xcube*X1*X1*X1)+(xsquare*X1*X1)+(x*X1)+constant)/((xcube*3*X1*X1)+(xsquare*2*X1)+x)))

print ("Root at second approximations:",X2)

X3= X2-((((xcube*X2*X2*X2)+(xsquare*X2*X2)+(x*X2)+constant)/((xcube*3*X2*X2)+(xsquare*2*X2)+x)))

print ("Root at thrid approximations:",X3)

X4= X3-((((xcube*X3*X3*X3)+(xsquare*X3*X3)+(x*X3)+constant)/((xcube*3*X3*X3)+(xsquare*2*X3)+x)))

print ("Root at fourth approximations:",X4)

X5= X4-((((xcube*X4*X4*X4)+(xsquare*X4*X4)+(x*X4)+constant)/((xcube*3*X4*X4)+(xsquare*2*X4)+x)))

print ("Root at fifth approximations:",X5)

# The Newton-Raphson method (also known as Newton's method) is a way

# to quickly find a good approximation for the root of a real-valued function

xcube=int(input('Enter the values for Xcube: '))

xsquare=int(input('Enter the values for Xsquare: '))

x=int(input('Enter the values for X: '))

constant=int(input('Enter the values for Constant: '))

X0=int(input('Enter the values for inital vaule X0: '))

# It can be any value, but based on the incorrectness the root convergence

# will delay. Here we can use trail and error method for input value.

X1= X0-((((xcube*X0*X0*X0)+(xsquare*X0*X0)+(x*X0)+constant)/((xcube*3*X0*X0)+(xsquare*2*X0)+x)))

print ("Root at first approximations:",X1)

X2= X1-((((xcube*X1*X1*X1)+(xsquare*X1*X1)+(x*X1)+constant)/((xcube*3*X1*X1)+(xsquare*2*X1)+x)))

print ("Root at second approximations:",X2)

X3= X2-((((xcube*X2*X2*X2)+(xsquare*X2*X2)+(x*X2)+constant)/((xcube*3*X2*X2)+(xsquare*2*X2)+x)))

print ("Root at thrid approximations:",X3)

X4= X3-((((xcube*X3*X3*X3)+(xsquare*X3*X3)+(x*X3)+constant)/((xcube*3*X3*X3)+(xsquare*2*X3)+x)))

print ("Root at fourth approximations:",X4)

X5= X4-((((xcube*X4*X4*X4)+(xsquare*X4*X4)+(x*X4)+constant)/((xcube*3*X4*X4)+(xsquare*2*X4)+x)))

print ("Root at fifth approximations:",X5)

### To read a coordinate point in a XY coordinate system and determine its Quadrant

x=int(input('Enter the values for X'))

y=int(input('Enter the values for Y'))

if x > 0 and y > 0:

print ('x, y point lies in the First quandrant')

elif x < 0 and y > 0:

print ('x, y point lies in the Second quandrant')

elif x < 0 and y < 0:

print ('x, y point lies in the Third quandrant')

elif x > 0 and y < 0:

print ('x, y point lies in the Fourth quandrant')

elif x == 0 and y == 0:

print ('x, y point lies at the origin')

y=int(input('Enter the values for Y'))

if x > 0 and y > 0:

print ('x, y point lies in the First quandrant')

elif x < 0 and y > 0:

print ('x, y point lies in the Second quandrant')

elif x < 0 and y < 0:

print ('x, y point lies in the Third quandrant')

elif x > 0 and y < 0:

print ('x, y point lies in the Fourth quandrant')

elif x == 0 and y == 0:

print ('x, y point lies at the origin')

### Reading files into Python

f = open("1.txt")

#create a text file which consists of names of students in class

# Printing file all the names

print("File contnet as in text file:",f.read())

f = open("1.txt")

# Printing file one by one letters

print("\nFile contnet one by one word fromtext file:")

next = f.read(1)

while next != "":

print(next)

next = f.read(1)

#create a text file which consists of names of students in class

# Printing file all the names

print("File contnet as in text file:",f.read())

f = open("1.txt")

# Printing file one by one letters

print("\nFile contnet one by one word fromtext file:")

next = f.read(1)

while next != "":

print(next)

next = f.read(1)

### Multiplication of two Matrices

X = [[4,1,7],[2,1,8],[3 ,7,1]];

Y = [[6,8,1],[9,7,5],[2,3,1]];

result = [[0,0,0],[0,0,0],[0,0,0]];

for i in range(len(X)):

for j in range(len(Y[0])):

for k in range(len(Y)):

result[i][j] += X[i][k] * Y[k][j]

for r in result:

print(r)

Y = [[6,8,1],[9,7,5],[2,3,1]];

result = [[0,0,0],[0,0,0],[0,0,0]];

for i in range(len(X)):

for j in range(len(Y[0])):

for k in range(len(Y)):

result[i][j] += X[i][k] * Y[k][j]

for r in result:

print(r)

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